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13f^2-15f+2=0
a = 13; b = -15; c = +2;
Δ = b2-4ac
Δ = -152-4·13·2
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$f_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$f_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{121}=11$$f_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-11}{2*13}=\frac{4}{26} =2/13 $$f_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+11}{2*13}=\frac{26}{26} =1 $
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